The correct option is B Consistent
The given linear equation are
⇒3x+2y−5=0 ....(1)
⇒a1=3,b1=−2,c1=−5
⇒2x−3y−7=0 .....(2)
⇒a2=2,b2=−3,c2=−7
⇒a1a2=32
⇒b1b2=2−3
⇒c1c2=−5−7
On comparing, we have
⇒a1a2,b1b2,c1c2
⇒a1a2≠b1b2
Hence, the following pair of equation is consistent.