The correct option is A Intersect at a point
The given linear equation are
⇒5x−4y+8=0....eq1
⇒a1=5,b1=−4,c1=8
⇒7x+6y−9=0...eq2
⇒a2=7,b2=6,c2=−9
⇒a1a2=57
⇒b1b2=−46
⇒c1c2=89
comparing
⇒a1a2,b1b2,c1c2
⇒a1a2≠b1b2
Hence,the line represented by eq1 and eq2 intersect at a point