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Balancing Chemical Equations by Partial Equation Method

On compete of...

Question

On compete of 2 gm methane $26575$ cals heat is generated . The heat of formation of methane will be (given heat of formation of $C O_{2}$ and $H_{2}$ O are - 97000a and - 68000 cals respectively ):

+ 20400 c a l s

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+ 20600 c a l s

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- 20400 c a l s

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- 2000 c a l s

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Solution

The correct option is C

- 20400 c a l s

For 2gm CH₄ -26575 cals
For 16gm -( 26575÷2)×16=212600
Now for C + 2H₂= CH₄
Heat of formation of CO₂ +2(heat of formation of H₂O ) -heat of combustion of CH₄ 
=-97000+2(-68000)-(-212600)
=-97000-136000+1212600
=-20400

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Similar questions

Q. On complete of combustion of 2 gm methane 26575 cals heat is generated. The heat of formation of methane will be :(given heat of formation of

C O_{2}

and

H_{2} O

are -97000 and -68000 cals respectively):

Q. On complete combustion of

2 g

methane

26575 C a l

heat is generated. The heat of formation of methane will be (given heat of formation of

C O_{2}

and

H_{2} O

are

- 97000

and

- 68000 C a l

respectively).

Q. If

C + O_{2} . ⟶ {C O}_{2} + 94.2 k c a l

H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} + 68.3 k c a l

{C H}_{4} + 2 O_{2} ⟶ {C O}_{2} + 2 H_{2} O + 210.8 k c a l

Then, the heat of formation of methane will be

Q. What will be the amount of heat evolved by burning

10 L

of methane under standard conditions?
(Given heats of formation of

C H_{4}, C O_{2} a n d H_{2} O a r e - 76.2, - 398.8 a n d - 241.6 k J m o l^{- 1}

respectively)

Q. What will be the heat of formation of methane, if the heat of combustion of carbon is

- x k J

, heat of formation of water is

- y k J

and heat of combustion of methane is

z k J

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On compete of 2 gm methane 26575 cals heat is generated . The heat of formation of methane will be (given heat of formation of CO2 and H2O are - 97000a and - 68000 cals respectively ):

The correct option is C −20400calsFor 2gm CH4 -26575 calsFor 16gm -( 26575÷2)×16=212600Now for C + 2H2 = CH4Heat of formation of CO2 +2(heat of formation of H2O ) -heat of combustion of CH4 =-97000+2(-68000)-(-212600)=-97000-136000+1212600=-20400

On compete of 2 gm methane $26575$ cals heat is generated . The heat of formation of methane will be (given heat of formation of $C O_{2}$ and $H_{2}$ O are - 97000a and - 68000 cals respectively ):

The correct option is C $- 20400 c a l s$
For 2gm CH₄ -26575 cals
For 16gm -( 26575÷2)×16=212600
Now for C + 2H₂= CH₄
Heat of formation of CO₂ +2(heat of formation of H₂O ) -heat of combustion of CH₄
=-97000+2(-68000)-(-212600)
=-97000-136000+1212600
=-20400