Question

On decreasing temperature of following system at equilibrium ${CO}_{2\left(S\right)}\rightleftharpoons {CO}_{2\left(g\right)}:$

• A. there is no effect on the equilibrium state
• B. more ${CO}_2$ gas is formed
• C. more solid ${CO}_2$ is obtained
• D. none of above

Answer 1

The correct option is A there is no effect on the equilibrium state

Chemical equilibrium is the state in which both reactant and product are present in concentrations which have no further tendency to change with time, so there is no observable change in the properties of the system.

Change in temperature, only effects the reaction when $△ng$ varies.

So, $△ng=$ number of moles of product-number of a mole of reactant.

Since,

${CO}_2\left(s\right)\rightleftharpoons {CO}_2\left(g\right)$, there is no change in $△ng$ Hence, on decreasing temperature there is no effect on the equilibrium state.