Question

On dissolution of silver chloride in excess of ammonia we get the complex that carries the charge of $a$ units and number of ligands present in complex is $b$ , then the value of ($a$ + $b$) is:

Answer 1

On dissolution of silver chloride in excess of ammonia we get the complex $\left[Ag\right(N{H}_3{)}_2{]}^{+}$.

The complex carries charge $=a=1$.

The number of ligands present $=b=2$

Therefore the value of ($a$ + $b$) =$3$