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Question

On dissolving 3.24 g of sulphur in 40 g of benzene, the boiling point of the solution was higher than that of benzene by 0.81 K. What is the molecular formula of sulphur?
(Given, Kb for benzene =2.53 Kkgmol−1, atomic mass of sulphur =32 gmol−1)

A
S4
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B
S8
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C
S2
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D
S6
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Solution

The correct option is B S8
The given values are:
weight of solute, WB=3.24 g
weight of solvent, WA=40 g
Tb=0.81 K; Kb=2.53 Kkgmol1
Using the formula,
MB=Kb×1000×WBTb×WA
we get,
MB=2.53×1000×3.240.81×40=253

Let the molecular formula of sulphur be Sx
The atomic mass of sulphur =32
Molecular mass =32×x
32x=253
x=25332=7.918
So, the molecular formula of sulphur =S8

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