On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
A
10
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B
11
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C
12
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D
13
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Solution
The correct option is A10 Clearly,(2272−875)=1397, is exactly divisible by N. Now, 1397=11×127 ∴ The required 3 -digit number is 127 , the sum of whose digits is 10.