On dividing 24xy2z2by 6yz2, we get
4xz
4xy
4xyz
Comparing the coefficients of the different elemnts and dividing, we get:
24/6 = 4;
x/1 = x;
y2/y = y;
z2/z2 = 1
Hence, we have 24xy2z3÷ 6yz2= 4xy.
On dividing (72p2q3)(r) by 24pq2, we get
On dividing (24xy2)(z2) by 6yz2, we get
On dividing 2mp2q−mqp+4npq2 by pq, what do we get?