Question

On dividing $76$ by a certain number $p$ the quotient is product of first two odd prime number , and remainder is number which is neither composite nor prime then $p$ lies in

• A. $\{1,2,3,\}$
• B. $\{4,5\}$
• C. $\{6,7,8\}$
• D. $\{9,10\}$

Answer 1

The correct option is B $\{4,5\}$

$76=p\ast Q+R$, $Q=3\times 5=15,R=1$
$76=p\ast 15+1$
This gives $p$as $5$.Hence, falls under option B.