Question

On dividing Rs. $1850$ into two parts $1st$ part is invested at $5$% and the second part is invested at $10$%. If the interest is compounded annually, then amounts become same in two years. What is the amount that is invested at $10$%?

• A. Rs. $968$
• B. Rs. $882$
• C. Rs. $920$
• D. Rs. $1,020$

Answer 1

The correct option is B Rs. $882$

Amount invested at $5$% is P and at $10$% is $(1850-P)$ According to the question.
$P{(1+\frac{5}{100})}^2=(1850-P){(1+\frac{10}{100})}^2$
$\frac{1850P}{P}==\frac{{(1+\frac{5}{100})}^2}{{(1+\frac{10}{100})}^2}$
$\frac{1850P}{P}=\frac{(105{)}^2}{(100{)}^2}$
$22\times 22(1850-P)=21\times 21\left(P\right)$
$895400=925P$
P=$968$
Amount invested at $1000=Rs.882$