On diving a binomial by a monomial we can never get a -

binomial

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monomial

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can't be determined

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none of these

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Solution

The correct option is B monomial
On dividing a binomial by a monomial we will always get a binomial.
For example,
(a $^{2}$ + 2a) $\div$ a = a + 2

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Question 49

State whether the statement given is True or False.

If we add a monomial and binomial, then answer can never be a monomial.

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