Question

On Diwali Mr.Antriksh wants to light his house with a number of $10W\left(220V\right)$ bulbs in parallel. If the house circuit has a fuse of $5A$ then what is the maximum number of such bulbs he can use if he is not using any other electrical appliance in the circuit.

• A. $10$
• B. $11$
• C. $100$
• D. $110$

Answer 1

The correct option is D $110$

The power dissipated is given as $P=VI$
In this case, the power of each bulb is $10W$ which uses $220V$ supply.

So, the amount of current used by each bulb is $I=\frac{P}{V}=\frac{10}{220}=0.045A$.

Since, the fuse has a power rating of $5A$.

Hence, number of bulbs that can be used is given by ,

$n=\frac{5A}{0.045A}=111.11$

Hence, $111$ such bulbs can be connected in parallel with security.

Hence, Mr. Antriksh can use 110 bulbs without any problem.

The correct option is D.