On doubling the speed of of an object its:

K.E is doubled

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P.E is doubled

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Momentum is doubled

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Acceleration is doubled

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Solution

The correct option is C Momentum is doubled
$K E = \frac{1}{2} m v^{2}$
therefore, KE quadruples on doubling speed
PE does not depend on speed.
$p = m v$
Therefore momentum doubles on doubling speed.

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