On electrolysis of Brine solution, is produced at anode and , at cathode.

C l_{2}

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H_{2}

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O_{2}

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N a

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Solution

The correct options are
A $C l_{2}$
B $H_{2}$
Brine solution is the concentrated solution of $N a C l$ in water. There are $O H^{-}, C l^{-} a n d N a^{+}, H^{+}$ ions present. Due to higher concentrations, $C l^{-}$ is produced at anode and $H_{2}$ at cathode as below
$A t a n o d e : -$
$2 C l^{-} ⟶ C l_{2} + 2 e^{-}$
$A t c a t h o d e : -$
$2 N a^{+} + 2 e^{-} ⟶ 2 N a$
$2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}$

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