Question

On electrolysis of dil. sulphuric acid using platinum $Pt$ electrode, the product obtained at anode will be:

• A. $H_{2}S$ gas
• B. $S{O}_2$ gas
• C. $H_2$ gas
• D. $O_2$ gas

Answer 1

The correct option is D $O_2$ gas

Anode : $2H_{2}O\left(l\right)\to O_2\left(g\right)+4H^{+}\left(aq\right)+4e^{-}$
Cathode : $2H^{+}\left(aq\right)+2e^{-}\to H_2\left(g\right)$

discharge potential is higher for sulphate then hydroxide

$\therefore$ oxygen gas will be obtained at anode.