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Question

On electrolysis of dilute copper sulphate solution using platinum electrodes, the products obtained at cathode and anode respectively are:

A
H2 and O2
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B
Cu and O2
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C
H2 and SO2
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D
O2 and H2
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Solution

The correct option is B Cu and O2
Reduction potential of Cu2+ is higher than H+ hence Cu2+ will be reduced at cathode more easily.

Reaction at cathode:

Cu2+(aq)+2eCu(s)

Reaction at anode:

2H2O(l)O2(g)+4H+(aq)+4e

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