Question

On electrolysis of dilute sulphuric acid using platinum electrodes, the product obtained at the anode will be:

• A. Hydrogen
• B. Oxygen
• C. Hydrogen sulphide
• D. Sulphur oxide

Answer 1

The correct option is B Oxygen

Ans : B

Dissociation of sulfuric acid,

$H_{2}S{O}_4\to 2H^{+}\left(aq\right)+S{O}_4^{-2}\left(aq\right)$

Disssociation of water,

$H_{2}O\to H^{+}\left(aq\right)+O{H}^{-}\left(aq\right)$

At Anode : $4O{H}^{-}\to 2H_2{O}^{+}\left(l\right)+O_2\left(g\right)+4e^{-}$

At Cathode : $2H^{+}\left(aq\right)+2e^{-}\to H_2\left(g\right)$