Question

On electrolysis, which of the following does not give out oxygen?

• A. Acidic water using $Pt$ electrode
• B. Fused $NaOH$ using $Pt$ electrode
• C. Dilute $H_{2}S{O}_4$ using $Pt$ electrode
• D. Dilute $H_{2}S{O}_4$ using $Cu$ electrode

Answer 1

The correct option is D Dilute $H_{2}S{O}_4$ using $Cu$ electrode

In dilute $H_{2}S{O}_4$ with Cu electrode, the reactions occurs:

at anode: $Cu\to C{u}^{2+}+2e^{-}$

at cathode: $2H^{+}+2e^{-}\to H_2$

so, there is no liberation of oxygen in the electrolysis of Dil. $H_{2}S{O}_4$ using Cu electrode.
Option D is correct.