On Freundlich adsorption isotherm x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log(xm) vs logP is shown,
From the graph above, (xm) is proportional to:
A
P3/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
P4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
P2/3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
P3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CP2/3 Freundlich adsorption isotherm: xm=kP1n..(i)
Taking log both sides log(xm)=log(kP1n) log(xm)=log(k)+1nlogP
The slope is : 1n
From graph: Slope=23=1n
Putting in (i) xm=kP23