On halogenation, an alkane gives only one monohalogenated product. The alkane may be:
A
2-methyl butane
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B
2, 2-dimethyl propane
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C
cyclopentane
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D
both (b) and (c)
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Solution
The correct option is D both (b) and (c)
A contains 4 different H atoms that's why A gives 4 different mono halogenated product. But B and C have all equivalent H−atoms giving only one chlorinated (monosubstituted) product.