Question

On heating 0.32 g of an organic compound with conc. nitric acid and barium chloride, 0.932 g barium sulphate was obtained. Calculate the percentage of sulphur in the given compound.

• A. 45%
• B. 38%
• C. 40%
• D. 85%

Answer 1

The correct option is C 40%

Mass of organic compound $0.32g$

Mass of Barium sulphate $0.932g$

We know that $32g$ sulphur is present in $1$ mol of ${BaSO}_4$. Therefore, $233g$ ${BaSO}_4$ contains $32g$ sulphur

$\Rightarrow$ $M_1$ $g$ of ${BaSO}_4$ contains $32g$ sulphur.

$\therefore$ Percentage of sulphur $=32\times \frac{100}{233}\times \frac{0.932}{0.32}=40$%