On heating 4.9 g of $K C l O_{3}$ , the weight loss is found to be 0.384 g. The percentage of $K C l O_{3}$ decomposed is:

20%

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30%

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10%

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40%

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Solution

The correct option is A 20%
2mol $K C l O_{3}$ will produce 2mol KCl and 3 mol $O_{2}$
Molar mass $K C l O_{3}$ = $122.55 g / m o l$
Molar mass $O_{2}$ = $32 g / m o l$
0.384g mass loss = 0.384g $O_{2}$ produced
Mol $O_{2}$ produced = 0.384/32
= 0.012 mol $O_{2}$
This means that 0.0122/3 = 0.008 mol $K C l O_{3}$ decomposed
Mass of 0.008 mol $K C l O_{3}$ = 122.55 0.008
= 0.980g $K C l O_{3}$ decomposed
% $K C l O_{3}$ that decomposed = 0.980/4.9 *100
20% answer A

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