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Nitrogen Dioxide

On heating, c...

Question

On heating, chloric acid decomposes to:

H C l O_{4}, {C l}_{2}, O_{2}

and

H_{2} O

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H C l O_{2}, {C l}_{2}, O_{2}

and

H_{2} O

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H C l O, {C l}_{2} O

and

H_{2} O_{2}

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H C l, H C l O, {C l}_{2} O

and

H_{2} O

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Solution

The correct option is A $H C l O_{4}, {C l}_{2}, O_{2}$ and $H_{2} O$
On heating chloric acid decomposes to:

$3 H C l O_{3} Δ - \to H C l O_{4} + {C l}_{2} + 2 O_{2} + H_{2} O$

Suggest Corrections

Similar questions

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

C a C O_{3} + H C l \to C a C l_{2} + C O_{2} ↑ + H_{2} O

N a + H_{2} O \to N a O H + H_{2} ↑

(N H_{4})_{2} S O_{4} + C a (O H)_{2} \to C a S O_{4} + N H_{3} ↑ + H_{2} O

H g (N O_{3})_{2} \to H g + N O_{2} ↑ + O_{2} ↑

P b_{3} O_{4} + H C l \to P b C l_{2} + C l_{2} ↑ + H_{2} O

What is the product of the reaction of $H_{2} O_{2}$ with $C l_{2}$ ?

H C l O_{4}

H C l O

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6})]^{4 -}

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