On heating compound $(A)$ gives a gas $(B)$ which is a constituent of air. This gas when treated with $H_{2}$ in the presence of a catalyst gives another gas $(C)$ which is basic in nature. $(A)$ should not be:

${({NH}_{4})}_{2} {Cr}_{2} O_{7}$

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${NaN}_{3}$

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${NH}_{4} {NO}_{2}$

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$Pb {({NO}_{3})}_{2}$

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Solution

The correct option is D
$Pb {({NO}_{3})}_{2}$

The explanation for the correct option:
Option (C): $Pb {({NO}_{3})}_{2}$
According to the question, the compound $(C)$ must be ${NH}_{3}$ because it is a basic gas that is produced by the Haber process.
The Haber process, commonly known as the Haber-Bosch process, is a synthetic nitrogen fixation process and the primary industrial method used to produce ammonia when the catalyst is present. Therefore, the compound $(B)$ must be Nitrogen gas
Nitrogen gas is a constituent of air.
Hence, the compound $(A)$ must produce $N_{2}$ on heating.
$Pb {({NO}_{3})}_{2}$ does not produce $N_{2}$ on heating $\underset{Lead nitrate}{Pb {({NO}_{3})}_{2} (s)} \to \underset{Lead oxide}{PbO (s)} + \underset{Nitrogen dioxide}{2 {NO}_{2} (g)} + \underset{Oxygen}{\frac{1}{2} O_{2} (g)}$
Hence, it is the correct option.
The explanation for the incorrect option:
Option (A): ${({NH}_{4})}_{2} {Cr}_{2} O_{7}$
On heating, Ammonium dichromate undergoes decomposition resulting in the formation of chromium (III) oxide and nitrogen gas. $\underset{Ammonium dichromate}{{({NH}_{4})}_{2} {Cr}_{2} O_{7} (s)} \to \underset{Chromium oxide}{{Cr}_{2} O_{3} (s)} + \underset{nitrogen gas}{N_{2} (g)} + \underset{water}{4 H_{2} O (g)}$
Hence, it is an incorrect option.
Option (B): ${NaN}_{3}$
When sodium azide is heated it decomposes into sodium and nitrogen gas. $\underset{Sodium azide}{2 {NaN}_{3} (s)} \to \underset{Sodium}{2 Na (s)} + \underset{Nitrogen gas}{3 N_{2} (g)}$
Hence, it is an incorrect option
Option (C): ${NH}_{4} {NO}_{2}$
On heating Ammonium nitrite ${NH}_{4} {NO}_{2}$ it decomposes into nitrogen gas and water. $\underset{Ammonium nitrite}{{NH}_{4} {NO}_{2} (s)} \to \underset{Nitrogen gas}{N_{2} (g) ↑} + \underset{water}{2 H_{2} O (l)}$
Hence, it is an incorrect option.
Therefore, $(A)$ should not be $Pb {({NO}_{3})}_{2}$

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Question 59
A non-metal A, which is the largest constituent of air, when heated with $H_{2}$ in 1:3 ratio in the presence of catalyst $Fe$ , gives a gas B.
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On heating compound (A) gives a gas (B)which is a constituent of air. This gas when treated with H2 in the presence of a catalyst gives another gas (C) which is basic in nature. (A)should not be:

On heating compound $(A)$ gives a gas $(B)$ which is a constituent of air. This gas when treated with $H_{2}$ in the presence of a catalyst gives another gas $(C)$ which is basic in nature. $(A)$ should not be: