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Oxidation and Reduction

On heating le...

Question

On heating lead (II) nitrate gives a brown gas 'A' . The gas 'A' on cooling changes to colorless solid 'B' .Solid 'B' on heating with NO changes to a blue solid 'C'. Identify 'A' , 'B', 'C' and also write reactions involved and draw structures of 'B' and 'C'.

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Solution

Decomposition reaction of lead(II) nitrate

On heating, lead nitrate $[P b (N O_{3})_{2}]$ decomposes to give lead oxide $(P b O)$ , nitrogen dioxide $(N O_{2})$ and oxygen $O_{2}$ .

$2 P b (N O_{3})_{2}$
$↓$ Heat
$2 P b O + 4 N O_{2} + O_{2}$

(Nitrogen dioxide)
Brown color gas

Cooling of $N O_{2}$ gas

$N O_{2}$ gas on cooling changes to colorless solid $N_{2} O_{4}$ .

$2 N O_{2} \to N_{2} O_{4}$

Colorless solid

Reaction of $N_{2} O_{4}$ with NO.

$N_{2} O_{4}$ reacts with NO to give a blue solid compound $N_{2} O_{3}$ (nitrogen trioxide).

$2 N O + N_{2} O_{4} \to 2 N_{2} O_{3}$

Thus A: $N O_{2}$
B: $N_{2} O_{4}$
C: $N_{2} O_{3}$

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