On heating lead nitrate forms oxides of nitrogen and lead. The oxides formed are:

2 P b O + 4 N O_{2} + O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N O_{2}, P b O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N O, P b O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N O, P b O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 P b O + 4 N O_{2} + O_{2}$
$2 P b (N O_{3})_{2} Δ \to 2 P b O + 4 N O_{2} + O_{2}$

Suggest Corrections

Similar questions

Q. On heating, lead nitrate forms oxides of nitrogen and lead. The oxides formed are__________.

Q. When lead nitrate is heated, it breaks down into lead monoxide, nitrogen dioxide and oxygen.

2 P b (N O_{3})_{2} \to 2 P b O + 4 N O_{2} + O_{2}

The reaction is an example of:

Q. When lead nitrate is heated, it breaks down into lead monoxide, nitrogen dioxide and oxygen as given below:

2 P b (N O_{3})_{2} \to 2 P b O + 4 N O_{2} + O_{2}

The above reaction is an example of :

A student while heating solid lead nitrate taken in a test-tube would observe :
(1) white residue of PbO2
(2) green residue of NO₂
(3) yellow residue of PbO
(4) brown residue of NO

Which one is correct?

Pb(NO3)2----->PbO+2NO2+O2

2Pb(NO3)2----->2PbO+4NO2+O2

Join BYJU'S Learning Program

On heating lead nitrate forms oxides of nitrogen and lead. The oxides formed are:

The correct option is A 2PbO+4NO2+O22Pb(NO3)2Δ→2PbO+4NO2+O2

The correct option is A $2 P b O + 4 N O_{2} + O_{2}$
$2 P b (N O_{3})_{2} Δ \to 2 P b O + 4 N O_{2} + O_{2}$