Question

On hybridisation of one $s$ and one $p$ orbitals we get:

• A. two mutually perpendicular orbitals
• B. two orbitals at ${180}^o$
• C. four orbitals directed tetrahedrally
• D. three orbitals in a plane

Answer 1

Answer: (B)

two orbitals at ${180}^o$

A number of hybrid orbitals are equal to the number of combining atomic orbitals. In one $s$ and one $p$ orbital hybridization, number of hybrid orbitals will be two $sp$ orbitals. The two-hybrid orbitals are such that they are maximum apart. Therefore, will be at ${180}^{\circ }$ with respect to each other.

Hence, $B$ is correct.