On hydrolysis, diborane produces:

H_{3} B O_{2} + H_{2} O_{2}

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H_{3} B O_{3} + H_{2}

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B_{2} O_{3} + O_{2}

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H_{3} B O_{3} + H_{2} O_{2}

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Solution

The correct option is B $H_{3} B O_{3} + H_{2}$
Diborane react with water to give following products,
$B_{2} H_{6} + 6 H_{2} O \to 2 H_{3} B O_{3} + 6 H_{2}$
Hence option $B$ is correct answer.

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