Question

On increasing the pressure three fold, the rate of reaction of ${2H}_{2}S$ + $O_2$ $\to$ products would increase

• A. 3 times
• B. 9 times
• C. 12 times
• D. 27 times

Answer 1

The correct option is D 27 times

Rate$=$ $K_{p^2}{H}_{2}S\times P{O}_2=x$ $($rate$)$

On increasing the pressure three fold :

Rate$=$ $K{\left(3P_{H_{2}S}\right)}^2\left(3P{O}_2\right)$

$=$ $K\times 9{P^2}_{H_{2}S}\times 3P{O}_2$

$=$ $K\times 27\times P_{H_{2}S}\times P{O}_2=27$

the rate will increases $27$ times

Hence, option $\left(D\right)$ is correct answer.