wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

On increasing the temperature of gas contained in closed vessel by 1oC, the pressure increases by 0.4%. The initial temperature of gas is:

A
25k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
250k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2500ok
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
250oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 250k
From the ideal gas equation,
PV =nRT
According to question,
New temperature, T' = T+1
New pressure, P' = P+0.4% of P
P=100.4P100
Therfore,equation becomes (100.4P100)V=nR(T+1)
On dividing the two equations, we get
100.4100=T+1T
1.004=1+1T
1.0041=1T
T=10.004
Therefore, T = 250 K.
Hence,correct option is B.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon