On interchanging the digits of a two – digit number the number obtained is18 more than the original number.If the sum of the digits is 8, find the original number?

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Solution

The correct option is B
35

Let ten's digit = x.

Then unit's digit = ( 8 -x) $∴ [10 (8 - x) + x] - [10 x + (8 - x)] = 18 \Leftrightarrow 18 x = 54 \Leftrightarrow x = 3.$

So, ten's digit = 3 and untis digits = 5. Hence, original number = 35

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If the number obtained by interchanging the digits of a two digit number is $18$ more than the original number and the sum of the digits is $8$ then what is the original number?

Q. The sum of the digits of two digit number is

3

. The number obtained by interchanging the digit is

9

less than the original number. Find the original number.

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On interchanging the digits of a two – digit number the number obtained is18 more than the original number.If the sum of the digits is 8, find the original number?

The correct option is B 35 Let ten's digit = x. Then unit's digit = ( 8 -x) ∴[10(8−x)+x]−[10x+(8−x)]=18⇔18x=54⇔x=3. So, ten's digit = 3 and untis digits = 5. Hence, original number = 35

The correct option is B
35

Let ten's digit = x.

Then unit's digit = ( 8 -x) $∴ [10 (8 - x) + x] - [10 x + (8 - x)] = 18 \Leftrightarrow 18 x = 54 \Leftrightarrow x = 3.$

So, ten's digit = 3 and untis digits = 5. Hence, original number = 35