On long standing, bleaching powder undergoes auto-oxidation into:

C a (C l O_{3})_{2}, C a C l_{2}

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C a O, C a C l_{2}

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C a C l O, C a C l O_{3}

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C a C l O_{2}, C a C l_{2}

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Solution

The correct option is A $C a (C l O_{3})_{2}, C a C l_{2}$
On long standing, bleaching powder undergoes auto-oxidation into calcium chlorate $C a (C l O_{3})_{2}$ and $C a C l_{2}$ .
$6 C a O C l_{2} \to 6 C a (C l O_{3})_{2} + 5 C a C l_{2}$ .
The bleaching powder is $C a O C l_{2}$

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C a O + 2 H C l \to C a C l_{2} + H_{2} O

C a C l_{2}

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