On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is:
A
< 50 mL
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B
> 50 mL
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C
= 50 mL
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D
Can not be predicted
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Solution
The correct option is D < 50 mL The inter-particle forces in between CHCl3 and acetone increases due to H-bonding and thus ΔmixingV becomes negative. So the resulting solution will have a volume of less than 50 ml.