On mixing ethyl acetate with aqueous sodium chloride, the composition of the resulting solution is :

C H_{3} C O O C_{2} H_{5} + N a C l

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C H_{3} C O O N a + C_{2} H_{5} O H

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C H_{3} C O C l + C_{2} H_{5} O H + N a O H

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C H_{3} C l + C_{2} H_{5} C O O N a

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Solution

The correct option is A $C H_{3} C O O C_{2} H_{5} + N a C l$
$C H_{3} C O O C_{2} H_{5} + N a C l \to n o r e a c t i o n$

$N a C l$ is the salt of the strong acid ( $H C l$ ) and the strong base ( $N a O H$ ).

Its aqueous solution is neutral.

Ethyl acetate reacts only in acidic or alkaline solutions.

Option A is correct.

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Similar questions

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

C H_{3} C O O C_{2} H_{5} + H_{2} O H^{+} - - \to C H_{3} C O O H + C_{2} H_{5} O H

C H_{3} C O O N a + N a O H C a O - - \to C H_{4} + N a_{2} C O_{3}

C H_{3} C O O H + C_{2} H_{5} O H H_{2} S O_{4} - --- \to C H_{3} C O O C_{2} H_{5} + H_{2} O

2 C H_{3} C O O H + 2 N a \to 2 C H_{3} C O O N a + H_{2}

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

C H_{3} C O O N a + N a O H C a O - - \to C H_{4} + N a_{2} C O_{3}

C H_{3} C O O H + C_{2} H_{5} O H H_{2} S O_{4} - --- \to C H_{3} C O O C_{2} H_{5} + H_{2} O

2 C H_{3} C O O H + 2 N a \to 2 C H_{3} C O O N a + H_{2}

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

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