Question

On moving a charge of 20 coulombs by 2 cm, 2 J of work is done, then the potential difference between the points is:

• A. 0.1 V
• B. 8 V
• C. 2 V
• D. 0.5 V

Answer 1

The correct option is A 0.1 V

The potential difference between two points in an electric field is,
$V_A-V_B=\frac{W}{q_0}$
where W is work done by moving charge $q_0$ from point A to B.
So, $V_A-V_B=\frac{2}{20}=0.1V$