On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases.
Potassium forms $K^{+}$ ion but it does not form $K^{2 +}$ because of;

Very low value of $(I . E .)_{1} a n d (I . E .)_{2}$

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Very high value of $(I . E .)_{1} a n d (I . E .)_{2}$

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Low value of $(I . E .)_{1}$ and low value of $(I . E .)_{2}$

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Low value of $(I . E .)_{1}$ and high value of $(I . E .)_{2}$

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Solution

The correct option is D
Low value of $(I . E .)_{1}$ and high value of $(I . E .)_{2}$

$K I . E ._{1} - -- \to K^{+} I . E ._{2} - -- \to K^{2 +}$
$I . E ._{2} >>> I . E ._{1}$ $∴$ Potassium gets ionized only once after which attains inert gas configuration.
$K^{+} = 1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2} 3 p^{6}$

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On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases.
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On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases. Potassium forms K+ ion but it does not form K2+ because of;

The correct option is D Low value of (I.E.)1 and high value of (I.E.)2 KI.E.1−−−→K+I.E.2−−−→K2+ I.E.2>>>I.E.1 ∴ Potassium gets ionized only once after which attains inert gas configuration. K+=1s2, 2s2, 2p6, 3s2 3p6

On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases.
Potassium forms $K^{+}$ ion but it does not form $K^{2 +}$ because of;