On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases.
For the process
$A_{(g)} + e^{-} \to A_{(g)}^{-}; Δ H = x a n d A_{(g)}^{-} \to A_{(g)} + e^{-}; Δ H = y$
Select correct alternate:

Ionization energy of $A_{(g)}^{-}$ is y

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Electron affinity of $A_{(g)}$ is x

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Electron affinity of $A_{(g)}$ is -y

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All are correct statements

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Solution

The correct option is A
Ionization energy of $A_{(g)}^{-}$ is y

$Δ H_{e g} = - E . A$

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Similar questions

On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases.
For the process
$A_{(g)} + e^{-} \to A_{(g)}^{-}; Δ H = x a n d A_{(g)}^{-} \to A_{(g)} + e^{-}; Δ H = y$
Select correct alternate:

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Q. Assertion :Atomic size decreases across period but increases down a group of the periodic table. Reason: Moving from left to right across a period, electrons are added one at a time to the outer energy shell. Electrons within a shell cannot shield each other from the attraction to protons, while moving down a group in the periodic table, the number of electrons and filled electron shells increases.

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On moving across a period, the atomic size decreases and nuclear charge increases and therefore the force of attraction exerted by the nucleus on the electron in the outermost shell increases. For the process A(g)+e−→A−(g); ΔH=xand A−(g)→A(g)+e−; ΔH=y Select correct alternate:

The correct option is A Ionization energy of A−(g) is y ΔHeg=−E.A

The correct option is A
Ionization energy of $A_{(g)}^{-}$ is y

$Δ H_{e g} = - E . A$