On of the factors of $x^{3} - 2 x^{2} + 2 x - 1$ is.

x - 1

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x + 1

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x - 2

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x + 2

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Solution

The correct option is B $x - 1$
$p (x) = x^{3} - 2 x^{2} + 2 x - 1$
$p (1) = 0$
so $(x - 1)$ is a factor of $p (x)$

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Similar questions

$(x + 1)$ is a factor of the polynomial
(a) $x^{3} - 2 x^{2} + x + 2$ (b) $x^{3} + 2 x^{2} + x - 2$
(c) $x^{3} + 2 x^{2} - x - 2$ (d) $x^{3} + 2 x^{2} - x + 2$

Question :

One of the factors of x⁵+x+1 is

(1) 2x² - x - 1

(2) x³ - x²+ 1

(3) x² - 2x² + 1

(4) x³ + x² + 1

Q. State True or False:

x^{3} - 2 x^{2} - x + 2

= (x - 1) (x - 2) (x + 1)

Q. (x³ + 2x² + x + 2)

\div

-

If dividend = $x^{4} + x^{3} - 2 x^{2} + x + 1$ , divisor = x - 1 and remainder = 2. Find the quotient q(x).

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On of the factors of x3−2x2+2x−1 is.

The correct option is B x−1p(x)=x3−2x2+2x−1p(1)=0so (x−1) is a factor of p(x)

On of the factors of $x^{3} - 2 x^{2} + 2 x - 1$ is.

The correct option is B $x - 1$
$p (x) = x^{3} - 2 x^{2} + 2 x - 1$
$p (1) = 0$
so $(x - 1)$ is a factor of $p (x)$