Question

On oxidation with acidified $K_{2}C{r}_2{O}_7$, a compound gives a ketone which contains same number of carbon atoms as in initial compound. The compound is:

• A. aldehyde
• B. $1^0$ alcohol
• C. $2^0$ alcohol
• D. both $1^0$ and $2^0$ alcohols

Answer 1

Answer: (C)

$2^0$ alcohol

$K_{2}C{r}_2{O}_7$ being a strong oxidizing agent gives complete oxidation product (carboxylic acid) but with secondary alcohols, it gives only ketones. (It should be noted that only under extreme conditions of oxidation the reagent is capable of breaking $C-C$ bond). The no. of carbons are the same in both $2^o$ alcohol and ketone.
Option C is correct.