On passing $3$ amperes of electricity for $50$ minutes, $1.8$ gram metal deposits. The equivalent mass of metal is

20.5

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25.8

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19.3

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30.7

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Solution

The correct option is C $19.3$
We know that,
$E = \frac{F . w}{i t} = \frac{96500 \times 1.8}{3 \times 50 \times 60} = 19.3$ .
therefore option C is a correct answer.

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On passing 3 amperes of electricity for 50 minutes, 1.8 gram metal deposits. The equivalent mass of metal is

The correct option is C 19.3We know that,E=F.wit=96500×1.83×50×60=19.3.therefore option C is a correct answer.

On passing $3$ amperes of electricity for $50$ minutes, $1.8$ gram metal deposits. The equivalent mass of metal is

The correct option is C $19.3$
We know that,
$E = \frac{F . w}{i t} = \frac{96500 \times 1.8}{3 \times 50 \times 60} = 19.3$ .
therefore option C is a correct answer.