Question

On passing 3A of electricity for 50 min, 1.8 g metal deposits. The equivalent mass of metal is

• A. 39.9
• B. 38.3
• C. 19.3
• D. 9.3

Answer 1

The correct option is C

19.3

$W_{metal}=\frac{E\times I\times t}{96500}$

$=\frac{E\times 3\times 50\times 60}{96500}$

$\therefore E=\frac{96500\times w}{3\times 50\times 60}=\frac{96500\times 1.8}{3\times 50\times 60}=19.3$