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Question

On passing a current through molten KCl, 19.5 g of K is deposited. The amount of Al deposited by the same quantity of electricity if passed through molten AlCl3 is :


A
4.5 g
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B
9.0 g
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C
13.5 g
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D
27 g
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Solution

The correct option is A 4.5 g
Equivalent weight of potassium = 391=39

Equivalent weight of aluminum = 273=9

Mass of K deposited = 19.5g

Substituting the values in equation:

MassofAldepositedMassofKdeposited=Eq. WtofAlEq. WtofK

MassofAldeposited19.5=939

MassofAldeposited=939×19.5=4.5g.

Hence, option A is correct.

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