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Question

On passing a current through molten KCl, 19.5g of potassium is deposited. If the same quantity electricity is passed through molten AlCl3 is:


A
4.5 g
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B
9 g
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C
13.5 g
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D
2.7 g
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Solution

The correct option is A 4.5 g
The reactions involved are,
K+eK
Al3+3eAl
Aluminium requires 3 times the amount of electricity to deposit one mole,
Moles of K deposited =19.539=0.5
Moles of Al deposited =0.53=16
Mass of Al deposited =27×16

=4.5g


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