On passing excess $C O_{2}$ in aqueous solution of sodium carbonate, the substance obtained is :

N a O H

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N a H C O_{3}

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N a_{2} C O_{3} .10 H_{2} O

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N a_{2} C O_{3} . H_{2} O

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Solution

The correct option is B $N a H C O_{3}$
$N a_{2} C O_{3} + C O_{2} + H_{2} O \to 2 N a H C O_{3}$
Hence, sodium bicarbonate is formed on passing carbon dioxide in excess in aqueous solution of sodium carbonate. Hence, option B is the correct answer.

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