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Byju's Answer

Standard VII

Chemistry

Faraday's Second Law

On passing on...

Question

On passing one faraday of electricity through the electrolytic cells containing $A g^{+}, N i^{+ 2}$ and $C r^{+ 3}$ ions solution, the deposited $A g (A t . w t . = 108), N i (A t . w t . = 59) a n d C r (A t . w t . = 52)$ is

$\begin{matrix} A g (i n g m) & N i (i n g m) & C r (i n g m) a) & 108 & 59 & 52 b) & 108 & 29.5 & 17.3 c) & 36 & 19.6 & 17.3 d) & 108 & 108 & 108 \end{matrix}$

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Solution

The correct option is B b
Wt. of Ag deposited = Equivalent weight of Ag $= \frac{108}{1} = 108 g m$
Wt. of Ni deposited = Equivalent weight of Ni $= \frac{59}{2} = 29.5 g m$
Wt. of Cr deposited = Equivalent weight of Cr $= \frac{52}{3} = 17.3 g m$

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Similar questions

Q. On passing one faraday of electricity through the electrolytic cells containing

A g^{+}, N i^{+ 2}

and

C r^{+ 3}

ions solution, the deposited

A g (A t . w t . = 108), N i (A t . w t . = 59) a n d C r (A t . w t . = 52)

\begin{matrix} A g (i n g m) & N i (i n g m) & C r (i n g m) a) & 108 & 59 & 52 b) & 108 & 29.5 & 17.3 c) & 36 & 19.6 & 17.3 d) & 108 & 108 & 108 \end{matrix}

Q. On passing one faraday of electricity through the electrolytic cells containing

A g^{+}, N i^{+ 2}

and

C r^{+ 3}

ions solution, the deposited

A g (A t . w t . = 108), N i (A t . w t . = 59) a n d C r (A t . w t . = 52)

\begin{matrix} A g (i n g m) & N i (i n g m) & C r (i n g m) a) & 108 & 59 & 52 b) & 108 & 29.5 & 17.3 c) & 36 & 19.6 & 17.3 d) & 108 & 108 & 108 \end{matrix}

Q. On passing one faraday of electricity through the electrolytic cells containing

A g^{+}, N i^{+ 2}

and

C r^{+ 3}

ions solution, the deposited

A g (A t . w t . = 108), N i (A t . w t . = 59) a n d C r (A t . w t . = 52)

\begin{matrix} A g (i n g m) & N i (i n g m) & C r (i n g m) a) & 108 & 59 & 52 b) & 108 & 29.5 & 17.3 c) & 36 & 19.6 & 17.3 d) & 108 & 108 & 108 \end{matrix}

One Faraday of current was passed through the electrolytic cell placed in series containing solution of Ag $^{+}$ , Ni $^{+}$ , Cr $^{+}$ . the amount of Ag (at.wt.=108), Ni (at.wt.=59) and Cr (at.wt.=52) deposited will be :

Q. One Faraday of current was passed through the electrolytic cells placed in series containing a solution of

A g^{+}, N i^{2 +}

and

C r^{3 +}

respectively. The ratio of amounts of

A g, N i

and

C r

deposited will be:

[A t . w t .

A g = 108, N i = 59, C r = 52]

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On passing one faraday of electricity through the electrolytic cells containing Ag+,Ni+2 and Cr+3 ions solution, the deposited Ag (At.wt.=108), Ni(At.wt.=59) and Cr(At.wt.=52) is Ag(in gm)Ni(in gm)Cr(in gm)a)1085952b)10829.517.3c)3619.617.3d)108108108

The correct option is B bWt. of Ag deposited = Equivalent weight of Ag =1081=108 gm Wt. of Ni deposited = Equivalent weight of Ni =592=29.5 gm Wt. of Cr deposited = Equivalent weight of Cr =523=17.3 gm

The correct option is B b
Wt. of Ag deposited = Equivalent weight of Ag $= \frac{108}{1} = 108 g m$
Wt. of Ni deposited = Equivalent weight of Ni $= \frac{59}{2} = 29.5 g m$
Wt. of Cr deposited = Equivalent weight of Cr $= \frac{52}{3} = 17.3 g m$