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Hydrides of Group 16

On passing ...

Question

On passing ${S O}_{2}$ gas in acidified $K_{2} {C r}_{2} O_{7}$ solution, green colour is produced due to formation of:

C r {S O}_{4}

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K_{2} C r O_{4}

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{C r}_{2} {({S O}_{4})}_{3}

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{C r}_{2} O_{3}

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Solution

The correct option is C ${C r}_{2} {({S O}_{4})}_{3}$
Sulphur dioxide reacts with acidified potassium dichromate to form chromium sulphate , potassium sulphate and water. Potassium dichromateturns golden yellow solution of potassium dichromate green.
$S O_{2} + K_{2} C r_{2} O_{7} \to C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + H_{2} O$

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