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Question

On plotting the points O(0, 0), A(3, 0), B(3, 4), C(0, 4) and joining OA, AB, BC and CO which of the following figure is formed?
(a) Square
(b) Rectangle
(c) Trapezium
(d) Rhombus

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Solution


The given points are O(0, 0), A(3, 0), B(3, 4) and C(0, 4). These points can be plotted on the graph paper as shown below.



From the figure, we have

OA = 3 units, AB = 4 units, BC = 3 units and OC = 4 units

In quadrilateral OABC,

OA = BC = 3 units and AB = OC = 4 cm

Thus, the quadrilateral OABC is a rectangle.

Hence, the correct answer is option (b).

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