On prolonged exposure to air, sodium finally changes to:

N a_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} C O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N a O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $N a_{2} C O_{3}$
On exposure to air sodium first undergoes oxidation to form sodium oxide (minor) and sodium peroxide (major)
$2 N a + O_{2} \to N a_{2} O_{2}$
$4 N a + O_{2} \to 2 {N a}_{2} O$
The oxide formed then reacts with moisture.
${N a}_{2} O + H_{2} O \to 2 N a O H$
Sodium hydroxide then reacts with carbon dioxide gas in air.
$2 N a O H + {C O}_{2} \to {N a}_{2} {C O}_{3} + H_{2} O$
Thus, the final product obtained is Sodium Carbonate $({N a}_{2} {C O}_{3})$ .

Suggest Corrections

Similar questions

Silver article become black on prolonged exposure to air this is because

Silver jewellery becomes black on prolonged exposure to air, it is due to the formation of

{Ag}_{3} N

{Ag}_{2} O

{Ag}_{2} S

{Ag}_{2} S

{Ag}_{3} N

Join BYJU'S Learning Program