On putting some dil.HCl in soda extract having some sulphite ion, we get gas $X$ , which on reaction with Iodine gas gives :

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Sulphate ion

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NaCl

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None of the above

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Solution

The correct options are
A HI
B Sulphate ion
$N a_{2} S O_{3} + 2 d i l H C l ⟶ 2 N a C l + S O_{2} + H_{2} O$
When sulphur dioxide reacts with iodine in acidic medium,it produce iodine ion and sulphate ion.
$S O_{2} + I_{2} + H^{+} ⟶ S O_{4}^{2 -} + I^{-}$

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