Question

On reaction with $C{l}_2$, phosphorus forms two types of halides 'A' and 'B'. Halide 'A' is yellowish-white powder but halide 'B' is colourless oily liquid. What would be the hydrolysis products of 'A' and 'B' respectively?

• A. $H_{3}P{O}_4$,$H_{3}P{O}_3$
• B. $HOP{O}_3$, $H_{2}P{O}_2$
• C. $H_{3}P{O}_3$,$H_{3}P{O}_4$
• D. $HP{O}_3$,$H_{3}P{O}_3$

Answer 1

The correct option is A $H_{3}P{O}_4$,$H_{3}P{O}_3$

$P+C{l}_2⟶\underset{\left(B\right)}{PC{l}_3}+\underset{\left(A\right)}{PC{l}_5}$

$PC{l}_5+4H_{2}O⟶H_{3}P{O}_4+5HCl$

$PC{l}_3+3H_{2}O⟶H_{3}P{O}_3+3HCl$